Substitute d d (1 w2)1 2(d dw) which follows from (5 85) and Eq (5 85) into d2S d2 (d d) (dS d) to verify Eq (5 86) ...

Substitute d/d = - (1 - w2)1/2(d/dw) [which follows from (5.85)] and Eq. (5.85) into d2S/d2 =

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Substitute d/dθ = - (1 - w2)1/2(d/dw) [which follows from (5.85)] and Eq. (5.85) into d2S/dθ2 = (d/dθ) (dS/dθ) to verify Eq. (5.86).

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Quantum Chemistry

ISBN: 978-0321803450

7th edition

Authors: Ira N. Levine

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Question Posted: May 26, 2016 06:20 AM

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Substitute d/d = - (1 - w2)1/2(d/dw) [which follows from (5.85)] and Eq. (5.85) into d2S/d2 =

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Quantum Chemistry

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