Question: Suppose that f is nonnegative and continuous on [1, 2] and that 21xkf(x)dx = 5 + k2 for k = 0, 1, 2. Prove that
Suppose that f is nonnegative and continuous on [1, 2] and that ˆ«21xkf(x)dx = 5 + k2 for k = 0, 1, 2. Prove that each of the following statements is correct.
a)
![Suppose that f is nonnegative and continuous on [1, 2]](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/image/images10/741-M-N-A-D-I(332)-1.png)
(b)
![Suppose that f is nonnegative and continuous on [1, 2]](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/image/images10/741-M-N-A-D-I(332)-2.png)
c)
![Suppose that f is nonnegative and continuous on [1, 2]](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/image/images10/741-M-N-A-D-I(332)-3.png)
x2 fx+1)dx 2
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a 1 x 4 implies 1 x 2 ie 1 2x Thus by the Comparison Theore... View full answer
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