The acceleration of a particle moving only on a horizontal xy plane is given by a =
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The acceleration of a particle moving only on a horizontal xy plane is given by a = 3ti + 4tj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector r = (20.0m)i + (40.0m)j locates the particle, which then has the velocity vector v = (5.00m/s)i + (2.00m/s)j. At t = 4.00 s, what are
(a) Its position vector in unit-vector notation and
(b) The angle between its direction of travel and the positive direction of the x axis?
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We make use of Eq 416 and Eq 410 Using a 3t 4tj we have in ms vtv dt 500200 3...View the full answer
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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