Question: The amount a fish grows between ages t = 1 and t = 5 if it follows the differential equation dL/dt = 6.48e-0.09t with initial

The amount a fish grows between ages t = 1 and t = 5 if it follows the differential equation dL/dt = 6.48e-0.09t with initial condition L(0) = 5.0.
Find the change in the state variable between the given times first by solving the differential equation with the given initial conditions and then by using the definite integral.

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