Question: The authors of the paper Evaluating Existing Movement Hypotheses in Linear Systems Using Larval Stream Salamanders (Canadian Journal of Zoology [2009]: 292298) investigated whether water

The authors of the paper €œEvaluating Existing Movement Hypotheses in Linear Systems Using Larval Stream Salamanders€ (Canadian Journal of Zoology [2009]: 292€“298) investigated whether water temperature was related to how far a salamander would swim and whether it would swim upstream or downstream. Data for 14 streams with different mean water temperatures where salamander larvae were released are given (approximated from a graph that appeared in the paper). The two variables of interest are x = mean water temperature (°C) and y = net directionality, which was defined as the difference in the relative frequency of the released salamander larvae moving upstream and the relative frequency of released salamander larvae moving downstream. A positive value of net directionality means a higher proportion were moving upstream than downstream. A negative value of net directionality means a higher proportion were moving downstream than upstream.
The authors of the paper €œEvaluating Existing Movement Hypotheses in

a. Construct a scatterplot of the data. How would you describe the relationship between x and y?
b. Find the equation of the least-squares line describing the relationship between y = net directionality and x = mean water temperature.
c. What value of net directionality would you predict for a stream that had mean water temperature of 15 °C?
d. The authors state that €œwhen temperatures were warmer, more larvae were captured moving upstream, but when temperatures were cooler, more larvae were captured moving downstream.€ Do the scatterplot and least-squares line support this statement?
e. Approximately what mean temperature would result in a prediction of the same number of salamander larvae moving upstream and downstream?

Mean Temperature (x) Net Directionality (y) 6.17 8.06 8.62 10.56 12.45 11.99 12.50 17.98 18.29 19.89 20.25 19.07 17.73 19.62 -0.08 0.25 0.00 0.08 0.03 0.07 0.29 0.23 0.24 0.19 0.05 0.07

Step by Step Solution

3.50 Rating (170 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a There is one point 806 025 which is separated from the general pattern of the data If this point i... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

536-M-S-D-A (4194).docx

120 KBs Word File

Students Have Also Explored These Related Statistics Questions!

Related Book