Question: The capacitor of Problem 79 is initially charged to a 150-V potential difference. The plates are then physically separated by another 0.750 mm in such
(a) The new capacitance
(b) The new energy stored in the capacitor. Explain the result using conservation of energy.
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a Use Eq 1715 Compute the capacitance b From Problem 63 Q 18 nC Us... View full answer
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