Question: The following data were collected from a standard 0.505-in.-diameter test specimen of a copper alloy (l0 = 2.0 in.): After fracture, the total length was
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After fracture, the total length was 3.014 in., and the diameter was 0.374 in. Plot the engineering stress-strain curve and calculate
(a) The 0.2% offset yield strength;
(b) The tensile strength;
(c) The modulus of elasticity;
(d) The % elongation;
(e) The % reduction in area:
(f) The engineering stress at fracture;
(g) The true stress at necking; and
(h) The modulus of resilience.
Load lb 3000 6000 7500 9000 10,500 12,000 12.400 11.400 in 0.00000 0.00167 0.00333 0.00417 0.0090 0.040 0.26 0.50 (maximum load) 1.02 (fracture
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S F p 4 0505 2 F0200 e l 20 a 02 offset yield strength ... View full answer
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