Question: The potential energy of a mass m as a function of position is given by U(x) = U 0 (a + 1/a), where a =
The potential energy of a mass m as a function of position is given by U(x) = U0(a + 1/a), where a = x/a and a is a constant.
(a) Plot U(x) versus x for 0.1a < x < 3a.
(b) Find the value of x = x0 at stable equilibrium.
(c) Write the potential energy U(x) for x = x0 + ε, where ε is a small displacement from the equilibrium position x0.
(d) Approximate the 1/x term using the binomial expansion with r = ε/x0 << 1 and discarding all terms of power greater than r2.
(e) Compare your result with the potential for a simple harmonic oscillator. Show that the mass will undergo simple harmonic motion for small displacements from equilibrium and determine the frequency of this motion.

(1+r)" 1+ nr + , 2 , (-)(n 2) ; (2)(1) (- 1), |(1+)" 1+ mr + (3)(2)(1) +...
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a A plot of Ux versus xais shown b F 0 dUdx dUd ddx U 0 a 1 2 0 1 x 0 a c Ux 0 ... View full answer
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