Question: The potential for a mass hanging from a spring is V (y) = ky2/2+mgy, where y = 0 corresponds to the position of the spring

The potential for a mass hanging from a spring is V (y) = ky2/2+mgy, where y = 0 corresponds to the position of the spring when nothing is hanging from it. Find the frequency of small oscillations around the equilibrium point.

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