The pressure drop in a section of pipe can be calculated as ?? = f L?V 2
Question:
The pressure drop in a section of pipe can be calculated as ?? = fL?V2/2D
Where ? p = the pressure drop (Pa), ? = the friction factor, L = the length of pipe [m], p = density (kg/m3), V = velocity (m/s), and D = diameter (m). For trubulent flow, the Colebrook equation provides a means to calculate the friction factor,?
Where ? = the roughness (m), and Re = the Reynolds number, Re = ?VD/?
Where ? = dynamic viscosity (N. s/m2).
(a) Determine ?p for a 0.2-m-long horizontal stretch of smooth drawn tubing given p = 1.23 kg/m3, ? = 1.79 x 10-5 N. s/m2, D = 0.005 m, V = 40 m/s, and ? = 0.0015 mm. Use a numerical method to determine the friction factor. Note that smooth pipes with Re 5, a good initial guess can be obtained using the blasius formula, ? = 0.316/Re0.25,
(b) Repeat the computation but for a rougher commercial steel pipe (? = 0.045 mm).
Step by Step Answer:
Numerical Methods For Engineers
ISBN: 9780071244299
5th Edition
Authors: Steven C. Chapra, Raymond P. Canale