The reaction of a methyl ketone with iodine solution in the presence of aqueous sodium hydroxide is shown in the equation below:
RCOCH3() + 3l2(aq) + 4NaOH(aq)  RCOONa(aq) + CHl3(s) + 3Nal(aq) + 3H2O()
where R = H, alkyl or aryl group
i. Which part of the ketone molecule has been involved in the formation of an iodoform molecule?
ii. Use your answer to i to explain why cyclohexanone gives a negative reaction in the iodoform test.