Treatment of hydroxylamine (H2NOH) with an excess of Fe(III) results in the formation of N2O and an

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Treatment of hydroxylamine (H2NOH) with an excess of Fe(III) results in the formation of N2O and an equivalent amount of Fe(II):
2H2NOH + 4Fe3+ ( N2O(g) + 4Fe2+ +4H+ + H2O

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Fundamentals of Analytical Chemistry

ISBN: 978-0495558286

9th edition

Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch

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Question Posted: Apr 30, 2016 02:18 PM

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Treatment of hydroxylamine (H2NOH) with an excess of Fe(III) results in the formation of N2O and an

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2H NOH 4Fe 3 N 2 Og 4Fe 2 4H H ...View the full answer

Fundamentals of Analytical Chemistry

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