Two charges are placed between the plates of a parallel plate capacitor One charge is q1 and the other is q2 5 00 C The charge per unit area on each of the plates has a magnitude of 1 30 10 4 C m2 The magnitude of the force on q1 due to q2 equals the magnitude of the force on q1 due to the electric field of the parallel plate capacitor What is the distance r between the two charges

Question: Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +5.00 C. The

Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +5.00 µC. The charge per unit area on each of the plates has a magnitude of σ = 1.30 × 10-4 C/m2. The magnitude of the force on q1 due to q2 equals the magnitude of the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges?

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