Question: Two structures for the sugar glucose are shown on page 858. Interconversion of the open-chain and cyclic hemiacetal forms is catalyzed by either acid or
(a) Propose a mechanism for the cyclization, assuming a trace of acid is present.
(b) The cyclic hemiacetal is more stable than the open-chain form, so very little of the open-chain form is present at equilibrium.
Step by Step Solution
3.31 Rating (166 Votes )
There are 3 Steps involved in it
a b Yes the cyclic form of glucose will give a positive Tollens test In the basi... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
893-C-O-O-C (1740).docx
120 KBs Word File
