Using basic shape-factor definitions, estimate the equilibrium temperature of the planet Mars which has a diameter of 4150 miles and revolves around the sun at a distance of 141 x 106 miles. The diameter of the sun is 865,000 miles. Assume that both the planet Mars and the sun act as blackbodies with the sun having an equivalent blackbody temperature of 10,000 R. Then repeat your calculations assuming that the albedo of Mars (the fraction of the incoming radiation returned to space) is 0.15.GIVENThe planet Mars revolving around the sunDiameter of Mars (Dm) = 4150 milesDistance from the sun (Rms) = 141 x 106 milesDiameter of the sun (Ds) = 865,000 milesASSUMPTIONSBoth Mars and the sun act as blackbodiesThe sun has an equivalent blackbody temperature (Ts) of 10,000R

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T.-10,000 R Tm=? De= Rma - 141 x 106 ml = 865,000 ml Dm=4150 ml Sun, A Mars, A2