We saw in Section 11.5 that, to find the energies of the bonding and antibonding orbitals of

Question:

We saw in Section 11.5 that, to find the energies of the bonding and antibonding orbitals of a heteronuclear diatomic molecule, we need to solve the secular determinant where aA et aB and we have taken S = O. Equations 11.34a and 11.34b give the general solution to this problem. Here, we shall develop the result for the case (aB - aA) 2>>{32.
(a) Begin by showing that where E+ and E_ are the energies of the bonding and antibonding molecular orbitals, respectively.
(b) Now use the expansion to show that which is the limiting result used in Justification 11.4.

We saw in Section 11.5 that