We saw in Section 11.5 that, to find the energies of the bonding and antibonding orbitals of a heteronuclear diatomic molecule, we need to solve the secular determinant where aA et aB and we have taken S = O. Equations 11.34a and 11.34b give the general solution to this problem. Here, we shall develop the result for the case (aB - aA) 2>>{32.
(a) Begin by showing that where E+ and E_ are the energies of the bonding and antibonding molecular orbitals, respectively.
(b) Now use the expansion to show that which is the limiting result used in Justification 11.4.

- 0 1/2 (1+x)121