Question: With light falling normally on a diffraction grating, the angle of diffraction of second order is equal to 45 for a wavelength 1 = 0.65m.

With light falling normally on a diffraction grating, the angle of diffraction of second order is equal to 45° for a wavelength λ1 = 0.65μm. Find the angle of diffraction of third order for a wave length λ2 = 0.50μm.

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From the formula we have d sin 45 ... View full answer

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