At time t = 0, a 3.0 kg particle with velocity v = (5.0 m/s) (6.0
Question:
At time t = 0, a 3.0 kg particle with velocity v = (5.0 m/s)î – (6.0 m/s)ĵ is at x = 3.0 m,y = 8.0 m. It is pulled by a 7.0 N force in the negative x direction. About the origin, what are
(a) The particle's angular momentum,
(b) The torque acting on the particle, and
(c) The rate at which the angular momentum is changing?
Step by Step Answer:
Let r x y z k be the position vector of the object v v x v y v z k ...View the full answer
Related Video
In Physics, a force is an influence that can change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. In this video, the concept of force and torque is demonstrated with the practical application of changing the flat tire of the car.
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