Question: A rectangular block of height L and horizontal cross-sectional area A floats at the interface between two immiscible liquids, as shown below. (a) Derive a
A rectangular block of height L and horizontal cross-sectional area A floats at the interface between two immiscible liquids, as shown below.

(a) Derive a formula for the block density, pb, in terms of the fluid densities p1 and p2, the heights h0, h1, and h2, and the cross-sectional area A. (It is not necessary that all of these variables appear in the final result).?
(b) Force balances on the blocks can be calculated in two ways; (i) in terms of the weight of the block and the hydrostatic forces on the upper and lower block surfaces; and (ii) in terms of the weight of the block and the buoyant force on the block as expressed by Archimedes? principle. Prove that these two approaches are equivalent.
Fluid 1 P (g/cm) L Fluid 2 D(g/cm) | || | Block P. (g/cm)
Step by Step Solution
3.51 Rating (171 Votes )
There are 3 Steps involved in it
a Weight of block Sum of weights of displace... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (2 attachments)
13-E-C-E-C-P (79).pdf
180 KBs PDF File
13-E-C-E-C-P (79).docx
120 KBs Word File
