Question: (a) Show that the Petersen graph [Fig. 11.52(a)] has no Hamilton cycle but that it has a Hamilton path. (b) Show that if any vertex

(a) Show that the Petersen graph [Fig. 11.52(a)] has no Hamilton cycle but that it has a Hamilton path.
(b) Show that if any vertex (and the edges incident to it) is removed from the Petersen graph, then the resulting subgraph has a Hamilton cycle.

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a Consider the graph as shown in Fig 1152a We demonstrate one case Start at vertex a and consider th... View full answer

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