Question: An ideal gas with 3.00 mol is initially in state 1 with pressure p1 = 20.0 atm and volume V1 = 1500 cm3. First it
An ideal gas with 3.00 mol is initially in state 1 with pressure p1 = 20.0 atm and volume V1 = 1500 cm3. First it is taken to state 2 with pressure p2 = 1.50p1 and volume V2 = 2.00V1. Then it is taken to state 3 with pressure p3 = 2.00p1 and volume V3 = 0.500V1. What is the temperature of the gas in
(a) State L and
(b) State 2?
(c) What is the net change in internal energy from state 1 to state 3?
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a With P 200 101 105 Pa and V 00015 m the ideal gas law gives ... View full answer
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