Question: Consider the differential equation f + af + bf = g, where g is some fixed function. Assume that f0 is one solution of this
Find a solution to fʹʹ + fʹ - 6f = 2x3 - x2 - 2x.
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If fx x 3 3 then f x x 2 and f x 2x so f x f x 6fx 2x x 2 2x 3 Hence fx x ... View full answer
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