Determine the volume of sulfuric acid solution needed to prepare 37.4 g of aluminum sulfate, Al2(SO4)3, by
Question:
2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) → 3H2(g)
The sulfuric acid solution, whose density is 1.104 g/mL, contains 15.0% H2SO4 by mass.
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Use the formula mass of Al2SO 4 3 to convert to moles of ...View the full answer
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