Given the following data: 2O3(g) 3O2(g) H = 427 kJ O2(g) 2O(g) H = 495
Question:
2O3(g) → 3O2(g) ΔH = –427 kJ
O2(g) → 2O(g) ΔH = 495 kJ
NO(g) + O3(g) → NO2(g) + O2(g) ΔH = –199 kJ
Calculate ΔH for the reaction NO(g) + O(g) → NO2(g)
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NO O 3 NO 2 O 2 H 199 kJ ...View the full answer
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