Question: Given the following data: C2H2(g) + 5/2 O2(g) 2CO2(g) + H2O(l) H = 1300. kJ C(s) + O2(g) CO2(g) H = 394 kJ
C2H2(g) + 5/2 O2(g) → 2CO2(g) + H2O(l) ΔH = –1300. kJ
C(s) + O2(g) → CO2(g) ΔH = –394 kJ
H2(g) + ½ O2(g) → H2O(l) ΔH = -286 kJ
calculate ΔH for the reaction 2C(s) + H2(g) → C2H2(g)
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2 C 2 O 2 2 CO 2 H 2 394 kJ H 2 12 O 2 H 2 O H 286 kJ 2 CO 2 H 2 O C 2 H 2 52 O ... View full answer
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