An ideal gas flows adiabatically through a duct At section 1, p1 140 kPa, T1 260 deg C, and V1 75 m s Farther downstream, p2 30 kPa and T2 207 deg C Calculate V2 in m s and s2 minus s1 in J (kg sdot K) if the gas is (a) Air, k 1 4, and (b) Argon, k 1 67 Fig P9 1 pl 140 kPa TI 260C V1 75 m s p2 30 kPa T2 207

Question: An ideal gas flows adiabatically through a duct. At section 1, p1 = 140 kPa, T1 = 260°C, and V1 = 75 m/s. Farther downstream,

An ideal gas flows adiabatically through a duct. At section 1, p1 = 140 kPa, T1 = 260°C, and V1 = 75 m/s. Farther downstream, p2 = 30 kPa and T2 = 207°C. Calculate V2 in m/s and s2 − s1 in J/(kg ⋅ K) if the gas is
(a) Air, k = 1.4, and
(b) Argon, k = 1.67. Fig P9.1

pl 140 kPa TI = 260C V1 = 75 m/s p2 30 kPa T2 = 207

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a For air take k 140 R 287 Jkg K and cp 1005 Jkg K The adiabatic steadyflow energy equation 923 is ... View full answer

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