Question: If an unfair coin has P(H) = 2 / 5 and P(T) = 3 / 5, then what is the probability that six flips come

If an unfair coin has P(H) = 2 / 5 and P(T) = 3 / 5, then what is the probability that six flips come up with H, T, T, T, H, T in exactly this order?

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