Question: Pr(D) = 0.2, Pr(N) = 0.8, Pr(P | D) = 1.00, and Pr(P | N) = 0.05. Compare with the results in the text, when

Pr(D) = 0.2, Pr(N) = 0.8, Pr(P | D) = 1.00, and Pr(P | N) = 0.05. Compare with the results in the text, when the disease was much less common.
Consider a disease with an imperfect test. Let D denote the event of an individual having the disease, N the event of not having the disease, and P the event of a positive result on the test. In the above case, find Pr(D | P).

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