Question: Make the given changes in the indicated examples of this section, and then solve the resulting problems. In Example 6, change 2.00 s to 2.50s.

Make the given changes in the indicated examples of this section, and then solve the resulting problems.

In Example 6, change 2.00 s to 2.50s.


Data from Example 6

A pulley belt 10.0 ft long takes 2.00 s to make one complete revolution. The radius of the pulley is 6.00 in. What is the angular velocity (in revolutions per minute) of a point on the rim of the pulley? See Fig. 8.39.

Because the linear velocity of a point on the rim of the pulley is the same as the velocity of the belt, v = 10.0ft/2.00s = 5.00ft/s. The radius of the pulley is r = 6.00 in. = 0.500 ft, and we can find ω by substituting into Eq. (8.11). This gives us

V v = wr 5.00 || W= w(0.500) 10.0 rad/s


To convert this answer to revolutions per minute, we use the procedure described in Section 1.4:

V v = wr 5.00 || W= w(0.500) 10.0 rad/s

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