In Exercises show that the function represented by the power series is a solution of the differential
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In Exercises show that the function represented by the power series is a solution of the differential equation.
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y = Ÿ n=0 (−1)n x²n+1 (2n + 1)!' y" + y = 0
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y 1 x 1 n0 2n 1 S n1 y 1 ...View the full answer
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