Question: In Exercises show that the function represented by the power series is a solution of the differential equation. y = n=0 x2n (2n)!' y -

In Exercises show that the function represented by the power series is a solution of the differential equation.

y = n=0 x2n (2n)!' y" - y = 0

y = n=0 x2n (2n)!' y" - y = 0

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