Question: A ball thrown in the air vertically from ground level with initial velocity 18 m/s has height h(t) = 18t 9.8t 2 at time

A ball thrown in the air vertically from ground level with initial velocity 18 m/s has height h(t) = 18t − 9.8t² at time t (in seconds). Find the average height and the average speed over the time interval extending from the ball’s release to its return to ground level.

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Let ht 18t 98t The ball is at ground level when t 0 s and when 18 9 98 49 The average he... View full answer

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