A point mass (m) is located at the origin. Let (Q) be the flux of the gravitational
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A point mass \(m\) is located at the origin. Let \(Q\) be the flux of the gravitational field \(\mathbf{F}=-G m \frac{\mathbf{e}_{r}}{r^{2}}\) through the cylinder \(x^{2}+y^{2}=R^{2}\) for \(a \leq z \leq b\), including the top and bottom (Figure 18). Show that \(Q=-4 \pi G m\) if \(a
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b a m R
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Let the surface be oriented with normal vector pointing outward We denote by S1 S2 and S3 the cylinder the top and the bottom respectively These surfa...View the full answer
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