A cell was constructed with two lead electrodes The electrolyte in one compartment is 1 0 m Pb(NO 3 ) 2 (aq) In the other compartment, NaI has been added to a Pb(NO 3 ) 2 solution until a yellow precipitate forms and the concentration of I ions is 0 050 mol L 1 The potential of this cell is 0 155 V...

a Calculating Pb Concentration in the Second Compartment Write the Nernst equation The cell potentia ...

A cell was constructed with two lead electrodes. The electrolyte in one compartment is 1.0 m Pb(NO

Question:

A cell was constructed with two lead electrodes. The electrolyte in one compartment is 1.0 m Pb(NO₃)₂(aq). In the other compartment, NaI has been added to a Pb(NO₃)₂ solution until a yellow precipitate forms and the concentration of I^– ions is 0.050 mol · L^–1. The potential of this cell is +0.155 V at 298 K.

(a) Calculate the concentration of Pb⁺ ions in the second compartment.

(b) Calculate the solubility product of PbI^–.

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