The equilibrium constant for the binding of a substrate to the active site of an enzyme was

Question:

The equilibrium constant for the binding of a substrate to the active site of an enzyme was found to be 326 at 310 K. At the same temperature, the rate constant for the second-order binding reaction is 7.4 * 107 L · mol−1 · s−1. What is the rate constant for the loss of unreacted substrate from the active site (the reverse of the binding reaction)?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Chemical Principles The Quest For Insight

ISBN: 9781464183959

7th Edition

Authors: Peter Atkins, Loretta Jones, Leroy Laverman

Question Posted: