Determine the wavelength of light emitted when an electron in a hydrogen atom makes a transition from an orbital in n = 6 to an orbital in n = 5.

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SORT You are given the energy levels of an atomic transition and asked to find the wavelength of emitted light. STRATEGIZE In the first part of the conceptual plan, calcu- late the energy of the electron in the n = 6 and n = 5 orbitals using Equation 8.7 and subtract to find AEatom In the second part, find Ephoton by taking the negative of AEatom and then calculate the wavelength corresponding to a photon of this energy using Equation 8.3. (The difference in sign between Ephoton and AEatom applies only to emission. The energy of a photon must always be positive.) GIVEN: n = 6→ n = 5 FIND: A CONCEPTUAL PLAN n = 5, n = 6 AE atom AEatom AE atom-Es-E6 Ephoton AEatom =-Ephoton RELATIONSHIPS USED En = -2.18 × 10-18 J(1/n²) E = hc/λ hc E = - λ λ