A soda can at 80F is put into a cooler containing ice at 32F. Its temperature after
Question:
A soda can at 80°F is put into a cooler containing ice at 32°F. Its temperature after 1 minutes is T(t) = 32 + 48 (0.9)t.
(a) Evaluate T (30) and interpret your results.
(b) How long did it take for the soda to cool to 50°F?
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a b Tt 324809 T3...View the full answer
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Related Book For
College Algebra With Modeling And Visualization
ISBN: 9780134418049
6th Edition
Authors: Gary Rockswold
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