Calculate the power of the eye when viewing objects at the greatest and smallest distances possible with
Question:
Calculate the power of the eye when viewing objects at the greatest and smallest distances possible with normal vision, assuming a lens-to-retina distance of 2.00 cm (a typical value).
Strategy
For clear vision, the image must be on the retina, and so di = 2.00 cm here. For distant vision, do ≈ ∞, and for close vision, do = 25.0 cm, as discussed earlier. The equation as written just above, can be used directly to solve for P in both cases, since we know di and do. Power has units of diopters, where 1 D = 1/m, and so we should express all distances in meters.
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