# Visible light of wavelength 550 nm falls on a single slit and produces its second diffraction minimum

## Question:

Visible light of wavelength 550 nm falls on a single slit and produces its second diffraction minimum at an angle of 45.0° relative to the incident direction of the light.

(a) What is the width of the slit?

(b) At what angle is the first minimum produced?

**Strategy**

From the given information, and assuming the screen is far away from the slit, we can use the equation D sin θ = mλ first to find D, and again to find the angle for the first minimum θ_{1}.

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## Step by Step Answer:

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