Question: Given the difference equation where e(k)= x(k+ 2) + 3x (k+1) + 2x(k)= e(k) 1, k=0 0, otherwise x(0) = 1 x(1) = -1 (a)

Given the difference equation where e(k)= x(k+ 2) + 3x (k+1) + 2x(k)= e(k) 1, k=0 0, otherwise x(0) = 1 x(1) = -1 (a) Solve for x(x) as a

where e(k)= x(k+ 2) + 3x (k+1) + 2x(k)= e(k) 1, k=0 0, otherwise x(0) = 1 x(1) = -1 (a) Solve for x(x) as a function of k. (b)Evaluate x(0), x(1), x(2), and x(3) in part (a). (c) Verify the results in part (b) using the power-series method. (d) Verify the results in part (b) by solving the difference equation directly.

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