Given the difference equation [ x(k+3)-2.2 x(k+2)+1.57 x(k+1)-0.36 x(k)=e(k) ] where (e(k)=1) for all (k geq 0),

Question:

Given the difference equation

\[
x(k+3)-2.2 x(k+2)+1.57 x(k+1)-0.36 x(k)=e(k)
\]

where \(e(k)=1\) for all \(k \geq 0\), and \(x(0)=x(1)=x(2)=0\).

(a) Write a digital computer program that will calculate \(x(k)\). Run this program solving for \(x(3), x(4), \ldots\), \(x(25)\).

(b) Using the sequential technique, check the values of \(x(k), 0 \leq k \leq 5\).

(c) Use the \(z\)-transform and the power-series method to verify the values \(x(k), 0 \leq k \leq 5\).

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Related Book For  answer-question

Digital Control System Analysis And Design

ISBN: 9781292061221

4th Global Edition

Authors: Charles Phillips, H. Nagle, Aranya Chakrabortty

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