Prove that if [operatorname{logit}left(operatorname{Pr}left(y_{i}=1 mid mathbf{x}_{i} ight) ight)=beta_{0}+mathbf{x}^{top} boldsymbol{beta}] and [operatorname{logit}left(operatorname{Pr}left(y_{i}=0 mid mathbf{x}_{i} ight) ight)=alpha_{0}+mathbf{x}^{top} boldsymbol{alpha}] then
Question:
Prove that if
\[\operatorname{logit}\left(\operatorname{Pr}\left(y_{i}=1 \mid \mathbf{x}_{i}\right)\right)=\beta_{0}+\mathbf{x}^{\top} \boldsymbol{\beta}\]
and
\[\operatorname{logit}\left(\operatorname{Pr}\left(y_{i}=0 \mid \mathbf{x}_{i}\right)\right)=\alpha_{0}+\mathbf{x}^{\top} \boldsymbol{\alpha}\]
then \(\beta_{0}=-\alpha_{0}\) and \(\boldsymbol{\beta}=-\boldsymbol{\alpha}\).
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Related Book For
Applied Categorical And Count Data Analysis
ISBN: 9780367568276
2nd Edition
Authors: Wan Tang, Hua He, Xin M. Tu
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