Air discharges downward in the pipe and then outward between the parallel disks. Assuming negligible density change in the air, derive a formula for the acceleration of air at point A, which is a distance r from the center of the disks. Express the acceleration in terms of the constant air discharge Q, the radial distance r, and the disk spacing h. If D = 10 cm, h = 0.6 cm, and Q = 0.380 m³/s, what are the velocity in the pipe and the acceleration at point A, where r = 20 cm?

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D h >•A - Elevation view Plan view