The Haaland formula for the friction factor is [ f=frac{0.3086}{left{log left[6.9 / operatorname{Re}+(varepsilon / 3.7 D)^{1.11} ight]

The Haaland formula for the friction factor is

\[ f=\frac{0.3086}{\left\{\log \left[6.9 / \operatorname{Re}+(\varepsilon / 3.7 D)^{1.11}\right]\right\}^{2}} \]

Compare this equation for \(f\) for \(\varepsilon / D=0.00001,0.0001,0.001\), and 0.01 and Reynolds numbers of \(10^{4}, 10^{5}, 10^{6}\), and \(10^{7}\) with the Moody chart and decide whether it is an acceptable replacement for the Colebrook formula.