# For the application at hand, the flow rate of Prob. 1436 is not adequate. At least 9 Lpm is required.

## Question:

For the application at hand, the flow rate of Prob. 14–36 is not adequate. At least 9 Lpm is required. Repeat Prob. 14–36 for a more powerful pump with H_{0} = 8.13 m and a = 0.0297 m/(Lpm)^{2}. Calculate the percentage improvement in flow rate compared to the original pump. Is this pump able to deliver the required flow rate?

**Data from Problem 14–36**

The performance data of a water pump follow the curve fit H_{available} = H_{0} – aV̇^{2}, where the pump’s shutoff head H_{0} = 7.46 m, coefficient a = 0.0453 m/(Lpm)^{2}, the units of pump head H are meters, and the units of V̇ are liters per minute (Lpm). The pump is used to pump water from one large reservoir to another large reservoir at a higher elevation. The free surfaces of both reservoirs are exposed to atmospheric pressure. The system curve simplifies to H_{required} = (z_{2} – z_{1}) + bV̇^{2}, where elevation difference z_{2} – z_{1} = 3.52 m, and coefficient b = 0.0261 m/(Lpm)^{2}. Calculate the operating point of the pump (V̇_{operating }and H_{operating}) in appropriate units (Lpm and meters, respectively).

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**Related Book For**

## Fluid Mechanics Fundamentals And Applications

**ISBN:** 9780073380322

3rd Edition

**Authors:** Yunus Cengel, John Cimbala

**Question Details**

**14**- TURBOMACHINERY

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