Both Mg 2+ and Cu 2+ are present in the same aqueous solution. Which of the following

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Both Mg²⁺ and Cu²⁺ are present in the same aqueous solution. Which of the following reagents would work best in separating these ions, precipitating one and leaving the other in solution: NaOH(aq), HCl(aq), NH₄Cl(aq), or NH₃(aq)? Explain your choice.

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To separate Mg2 and Cu2 ions in an aqueous solution we need to identify a reagent that can selectively precipitate one ion while leaving the other in solution Among the options provided the most suitable reagent for this separation is NaOHaq or sodium hydroxide Heres the reasoning behind this choice When NaOHaq is added to a solution containing both Mg2 and Cu2 ions there will be a difference in their behavior due to the different solubility properties of their hydroxide precipitates MgOH2 is a sparingly soluble compound while CuOH2 is more soluble When NaOHaq is added Mg2 ions react with OH ions to form a white precipitate of MgOH2 according to the following balanced equation Mg2aq 2OHaq MgOH2s The resulting MgOH2 precipitate has low solubility and will be visible as a solid substance in the solution On the other hand Cu2 ions do not readily react with OH ions to form a precipitate and remain in solution as Cu2aq By carefully observing the reaction mixture the formation of a white precipitate indicates the presence of Mg2 ions and the remaining solution suggests the presence of Cu2 ions Therefore adding NaOHaq to the solution containing Mg2 and Cu2 ions would allow for the selective ...View the full answer

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