Question: For polyprotic acids, ionization constants for successive ionization steps decrease rapidly. That is,K a1 K a2 K a3 . The ionization constants for
For polyprotic acids, ionization constants for successive ionization steps decrease rapidly. That is,Ka1 ≫ Ka2 ≫ Ka3. The ionization constants for the first two steps in the ionization of [Fe(H2O)6]3+ (reactions 24.10 and 24.11) are more nearly equal in magnitude. Why does this multistep ionization seem not to follow the pattern for polyprotic acids?
Reaction 24.10
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Reaction 24.11
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[Fe(HO)6]+ + HO = [FeOH(HO)5]2+ + H3O+ K =9 x 104 (24.10)
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The ionization of FeH2O63 involves multiple steps leading to the formation of various species with d... View full answer
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