Question: A weight W is supported by two cables anchored a distance D apart (see Figure P35). The cable length L AB is given, but the

A weight W is supported by two cables anchored a distance D apart (see Figure P35). The cable length LAB is given, but the length LAC is to be selected. Each cable can support a maximum tension force equal to W.


Figure P35.

 D C A LAB LẠC B W to


For the weight to remain stationary, the total horizontal force and total vertical force must each be zero. This principle gives the equations

D C A LAB LC B W to


We can solve these equations for the tension forces TAB and TAC if we know the angles θ and ϕ. From the law of cosines


From the law of sines


For the given values D = 6 ft, LAB = 3 ft, and W = 2000 lb, use a loop in MATLAB to find LAcmin, the shortest length LAC we can use without TAB or TAC exceeding 2000 lb. Note that the largest LAC can be is 6.7 ft (which corresponds to 0 = 90°). Plot the tension forces TAB and TAC on the same graph versus LAC for LAanin ≤ LAC ≤ 6.7.

D C A LAB LC B W to

Step by Step Solution

3.43 Rating (172 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Introduction Mechanical Engineering Questions!