Question: please help in mat lab mat lab 5. A weight W is supported by two cables anchored a distance D apart, as seen in Fig.

please help in mat labplease help in mat labmat lab 5. A weight W is supportedmat lab

5. A weight W is supported by two cables anchored a distance D apart, as seen in Fig. 1. The cable length LAR is given, but the length of LAG is to be calculated. Each cable can support a AB AC Figure 1: maximum tension force equal to W. For the weight to remain stationary, the total horizontal force and total vertical force must each be zero. This results in a summing of forces TAB cos(0)+TAC cos(d) TAB sin()+TAC sin() 0 W = = Using the law of sines and cosines 2 COS 2DLAB AB sin(G LAC With this information, use a for loop in Matlab to find the minimum value for LAC, where D 8.0ft, LAB - 4.0ft, and W - 2850lbs, with the tension values TAB or Tac not exceeding 2550 lbs on the cables. Note that LAc can be up to 8.9443 feet long, which is when 0 - 90. After solving the system, plot TaB and Tac versus LAB 0.5 3 LAc S8.9443. 5. A weight W is supported by two cables anchored a distance D apart, as seen in Fig. 1. The cable length LAR is given, but the length of LAG is to be calculated. Each cable can support a AB AC Figure 1: maximum tension force equal to W. For the weight to remain stationary, the total horizontal force and total vertical force must each be zero. This results in a summing of forces TAB cos(0)+TAC cos(d) TAB sin()+TAC sin() 0 W = = Using the law of sines and cosines 2 COS 2DLAB AB sin(G LAC With this information, use a for loop in Matlab to find the minimum value for LAC, where D 8.0ft, LAB - 4.0ft, and W - 2850lbs, with the tension values TAB or Tac not exceeding 2550 lbs on the cables. Note that LAc can be up to 8.9443 feet long, which is when 0 - 90. After solving the system, plot TaB and Tac versus LAB 0.5 3 LAc S8.9443

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