Calculate \(\Delta G_{298}^{0}\) at 1 bar and \(298.15 \mathrm{~K}\) for the following reaction:

\[ \mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{SO}_{3}(\mathrm{~g}) \]

Given that \(\Delta G_{f, \mathrm{SO}_{3}}^{0}=-370.532 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta G_{f, \mathrm{SO}_{2}}^{0}=-300.612 \mathrm{~kJ} / \mathrm{mol}\).